Question : Write a program that will create 'n' number of user level threads. Inside each thread you have to print Fibonacci series up to a given numbers and make a sum of the series. For each thread you need to assign your own ID and store the sum of the series in a perfect place from where we can easily print which thread id produces which sum.
In the main function create a child and inside the child call all these threads to perform your operations. Inside the parent method just display "Operations are done! Congrats". You must ensure that the main function must wait until the child and thread execution terminates,
Code:
#include<stdio.h>
#include<pthread.h>
#include<stdlib.h>
#include<sys/types.h>
#include<sys/syscall.h>
#include<unistd.h>
#include<threads.h>
int n, count =0, sum=0;
void *threadFuction(void*);
long long arr[100000];
long long arr1[100000];
pthread_mutex_t mutex1= PTHREAD_MUTEX_INITIALIZER;
int main(void){
int i =0, retVal=0;
pthread_t *thread;
thread = (pthread_t*)malloc(n*sizeof(pthread_t));
for(i=0;i<4;i++){
printf(" %d_th number your ID: ",i);
scanf("%d",&n);
retVal = pthread_create(&thread[i],NULL,threadFuction,(void*)&n);
pthread_join(thread[i],NULL);
}
printf("\n Thread in and sum");
printf("\n");
for(int i=0;i<count;i++){
printf("\n");
printf("%lld %lld",arr[i],arr[i]);
printf("\n");
}
}
void *threadFuction(void *arg){
pthread_mutex_lock(&mutex1);
printf("\n");
int t1=0,t2=1;
int nextTerm = t1+t2;
printf("Fibonacci Series: %d,%d ",t1,t2);
sum = t1 + t2;
for(int i = 3;i<=n;i++){
printf("%d," ,nextTerm);
sum= sum+nextTerm;
t1=t2;
t2 = nextTerm;
nextTerm = t1+t2;
}
arr[count] = thrd_current();
arr1[count] = sum;
count++;
sum=0;
pthread_mutex_unlock(&mutex1);
printf("\n");
}
