Write a program that dynamically allocates memory to store n number of integers and deletes the duplicate values from the list. For example, if the list contains - 10, 6, 2, 10, 9; after deleting duplicate elements you will get the list - 10, 6, 2, 9. You must write a function, called DeleteDuplicate (int n, int *p), where n is the total array size and p is a pointer variable that have array address to solve the problem.
Code:
#include <stdio.h>
void DeleteDuplicate(int n, int *p){
printf("The array elements before removing duplicates: ");
for(int i=0;i<n;i++)
printf("%d ",p[i]);
printf("\n");
for(int m=0;m<n;m++)
{
for(int o=m+1;o<n;o++)
{
if(p[o]==p[m])
{
for(int k=o;k<(n-1);k++)
{
p[k]=p[k+1];
n--;
}
o--;
}
}
}
printf("The array elements before removing duplicates: ");
for(int i=0;i<n;i++)
printf("%d ",p[i]);
}
int main()
{
int array[] = {10, 6, 2, 10, 9};
DeleteDuplicate(sizeof(array)/sizeof(array[0]),array);
//return 0
return 0;
}
Run:
